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Evaluate: exe2x∫ex4e2x-1 dx

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Question

Evaluate: `int "e"^"x"/(4"e"^"2x" -1)` dx

Sum
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Solution

Let I = `int "e"^"x"/(4"e"^"2x" -1)` dx

`"I" = int "e"^"x"/(4("e"^"x")^2 - 1)` dx

Put ex = t

∴ ex  dx = dt

∴ I = `int "dt"/(4"t"^2 - 1)`

`∴ "I" = 1/4 int 1/("t"^2 - 1/4)` dt

`∴ "I" = 1/4 int 1/("t"^2 - (1/2)^2)` dt

`∴ "I" = 1/4 . 1/(2 (1/2)) log |("t" - 1/2)/("t" + 1/2)|` + c

`∴ "I" = 1/4 log |("2t" - 1)/("2t" + 1)|` + c

Resubstitute t = ex

`∴ "I" = 1/4 log |(2"e"^"x" - 1)/(2"e"^"x" + 1)|` + c

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Notes

Answer in the textbook is incorrect.

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Chapter 5: Integration - MISCELLANEOUS EXERCISE - 5 [Page 139]

APPEARS IN

Balbharati Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
Chapter 5 Integration
MISCELLANEOUS EXERCISE - 5 | Q IV. 3) viii) | Page 139

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