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Integrate the following w.r.t.x : log(1+cosx)-xtan(x2) - Mathematics and Statistics

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Question

Integrate the following w.r.t.x : `log (1 + cosx) - xtan(x/2)`

Sum
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Solution

Let I = `int [log(1 + cosx) - xtan(x/2)]*dx`

= `int [log(1 + cos.x)*1dx - intxtan (x/2)*dx`

= `[log(1 + cosx)]* int 1dx - int {d/dx [log (1 + cosx)]* int 1dx}*dx - xtan (x/2)*dx`

= `[log (1 + cosx)]*(x) - int 1/(1 + cosx)*(0 - sin x)*xdx - int x tan (x/2)*dx`

= `x*log(1 + cosx) + intx* (sinx)/(1 + cosx)*dx - int xtan (x/2)*dx + c`

= `x*log(1 + cosx) + intx*(2sin(x/2)*cos(x/2))/(2cos^2(x/2)*dx - int xtan (x/2)*dx + c`

= `xlog (1 + cosx) + int x*tan(x/2)*dx - intxtan(x/2)*dx + c`

= x·log(1 + cosx) + c.

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Chapter 3: Indefinite Integration - Miscellaneous Exercise 3 [Page 150]

APPEARS IN

Balbharati Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
Chapter 3 Indefinite Integration
Miscellaneous Exercise 3 | Q 3.05 | Page 150

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