English

Choose the correct options from the given alternatives : ∫x-sinx1-cosx⋅dx =

Advertisements
Advertisements

Question

Choose the correct options from the given alternatives :

`int (x- sinx)/(1 - cosx)*dx` =

Options

  • `x cot (x/2) + c`

  • `- x cot (x/2) + c`

  • `cot (x/2) + c`

  • `x tan (x/2) + c`

MCQ
Advertisements

Solution

`- x cot (x/2) + c`

[ Hint : `int (x- sinx)/(1 - cosx)*dx = int (x - 2sin(x/2)cos(x/2))/(2sin^2 (x/2))*dx`

= `(1)/(2) int x"cosec"^2(x/2)*dx - int cot(x/2)*dx`

= `(1)/(2) [x int "cosec"^2 (x/2)*dx - int [d/dx(x) int "cosec"^2(x/2)^(dx)]*dx - int cot(x/2)*dx`

= `(1)/(2)[x{(-cot(x/2))/((1/2))} - int1* (-cot(x/2))/((1/2))*dx - intcot(x/2)*dx`

= `xcot(x/2) + int cot(x/2)*dx - int cot(x/2)*dx`

= `- x cot(x/2) + c`].

shaalaa.com
  Is there an error in this question or solution?
Chapter 3: Indefinite Integration - Miscellaneous Exercise 3 [Page 148]

APPEARS IN

Balbharati Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
Chapter 3 Indefinite Integration
Miscellaneous Exercise 3 | Q 1.06 | Page 148

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

`int1/xlogxdx=...............`

(A)log(log x)+ c

(B) 1/2 (logx )2+c

(C) 2log x + c

(D) log x + c


Integrate the function in x sin 3x.


Integrate the function in (sin-1x)2.


Integrate the function in x sec2 x.


Integrate the function in `(xe^x)/(1+x)^2`.


Integrate the function in `((x- 3)e^x)/(x - 1)^3`.


Integrate the function in e2x sin x.


Prove that:

`int sqrt(x^2 + a^2)dx = x/2 sqrt(x^2 + a^2) + a^2/2 log |x + sqrt(x^2 + a^2)| + c`


Evaluate the following:

`int x^2 sin 3x  dx`


Evaluate the following : `int x.sin^2x.dx`


Evaluate the following : `int e^(2x).cos 3x.dx`


Evaluate the following : `int cos sqrt(x).dx`


Evaluate the following:

`int x.sin 2x. cos 5x.dx`


Integrate the following functions w.r.t. x : `x^2 .sqrt(a^2 - x^6)`


Integrate the following functions w.r.t. x: `sqrt(x^2 + 2x + 5)`.


Choose the correct options from the given alternatives :

`int (log (3x))/(xlog (9x))*dx` =


Choose the correct options from the given alternatives :

`int (1)/(cosx - cos^2x)*dx` =


Integrate the following w.r.t.x : cot–1 (1 – x + x2)


Integrate the following w.r.t.x : `(1)/(xsin^2(logx)`


Integrate the following w.r.t.x : log (x2 + 1)


Integrate the following w.r.t.x : e2x sin x cos x


Integrate the following w.r.t.x : sec4x cosec2x


Evaluate the following.

`int x^2 e^4x`dx


Evaluate: `int ("ae"^("x") + "be"^(-"x"))/("ae"^("x") - "be"^(−"x"))` dx


Evaluate: `int "dx"/("9x"^2 - 25)`


Evaluate:

∫ (log x)2 dx


`int (sin(x - "a"))/(cos (x + "b"))  "d"x`


`int 1/x  "d"x` = ______ + c


`int (x^2 + x - 6)/((x - 2)(x - 1))  "d"x` = x + ______ + c


`int [(log x - 1)/(1 + (log x)^2)]^2`dx = ?


`int "e"^x [x (log x)^2 + 2 log x] "dx"` = ______.


`int "dx"/(sin(x - "a")sin(x - "b"))` is equal to ______.


The value of `int_0^(pi/2) log ((4 + 3 sin x)/(4 + 3 cos x))  dx` is


Evaluate: `int_0^(pi/4) (dx)/(1 + tanx)`


Find: `int e^x.sin2xdx`


If `int(2e^(5x) + e^(4x) - 4e^(3x) + 4e^(2x) + 2e^x)/((e^(2x) + 4)(e^(2x) - 1)^2)dx = tan^-1(e^x/a) - 1/(b(e^(2x) - 1)) + C`, where C is constant of integration, then value of a + b is equal to ______.


`int_0^1 x tan^-1 x  dx` = ______.


Evaluate: 

`int(1+logx)/(x(3+logx)(2+3logx))  dx`


Evaluate:

`int e^(logcosx)dx`


Evaluate the following.

`intx^3/sqrt(1+x^4)dx`


If f′(x) = 4x3 − 3x2 + 2x + k, f(0) = 1 and f(1) = 4, find f(x).


If ∫(cot x – cosec2 x)ex dx = ex f(x) + c then f(x) will be ______.


Evaluate the following.

`intx^2e^(4x)dx`


`∫ sin^(−1)` xdx is equal to ______.


Evaluate \[\int \frac{x\sin^{-1}x}{\sqrt{1-x^2}}\,dx.\]


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×