English

Choose the correct options from the given alternatives : ∫x-sinx1-cosx⋅dx =

Advertisements
Advertisements

Question

Choose the correct options from the given alternatives :

`int (x- sinx)/(1 - cosx)*dx` =

Options

  • `x cot (x/2) + c`

  • `- x cot (x/2) + c`

  • `cot (x/2) + c`

  • `x tan (x/2) + c`

MCQ
Advertisements

Solution

`- x cot (x/2) + c`

[ Hint : `int (x- sinx)/(1 - cosx)*dx = int (x - 2sin(x/2)cos(x/2))/(2sin^2 (x/2))*dx`

= `(1)/(2) int x"cosec"^2(x/2)*dx - int cot(x/2)*dx`

= `(1)/(2) [x int "cosec"^2 (x/2)*dx - int [d/dx(x) int "cosec"^2(x/2)^(dx)]*dx - int cot(x/2)*dx`

= `(1)/(2)[x{(-cot(x/2))/((1/2))} - int1* (-cot(x/2))/((1/2))*dx - intcot(x/2)*dx`

= `xcot(x/2) + int cot(x/2)*dx - int cot(x/2)*dx`

= `- x cot(x/2) + c`].

shaalaa.com
  Is there an error in this question or solution?
Chapter 3: Indefinite Integration - Miscellaneous Exercise 3 [Page 148]

APPEARS IN

Balbharati Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
Chapter 3 Indefinite Integration
Miscellaneous Exercise 3 | Q 1.06 | Page 148

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Prove that:

`int sqrt(x^2 - a^2)dx = x/2sqrt(x^2 - a^2) - a^2/2log|x + sqrt(x^2 - a^2)| + c`


`int1/xlogxdx=...............`

(A)log(log x)+ c

(B) 1/2 (logx )2+c

(C) 2log x + c

(D) log x + c


Integrate the function in x sin 3x.


Integrate the function in x sec2 x.


Integrate the function in tan-1 x.


`intx^2 e^(x^3) dx` equals: 


Evaluate the following:

`int x tan^-1 x . dx`


Evaluate the following : `int e^(2x).cos 3x.dx`


Evaluate the following : `int log(logx)/x.dx`


Evaluate the following : `int (t.sin^-1 t)/sqrt(1 - t^2).dt`


Integrate the following functions w.r.t. x : `e^(2x).sin3x`


Integrate the following functions w.r.t. x:

sin (log x)


Integrate the following functions w.r.t. x : `sqrt(5x^2 + 3)`


Integrate the following functions w.r.t. x : `x^2 .sqrt(a^2 - x^6)`


Integrate the following functions w.r.t. x : `sqrt(4^x(4^x + 4))`


Integrate the following functions w.r.t. x : `sec^2x.sqrt(tan^2x + tan x - 7)`


Integrate the following functions w.r.t. x : `e^x/x [x (logx)^2 + 2 (logx)]`


Integrate the following functions w.r.t. x : `log(1 + x)^((1 + x)`


Integrate the following w.r.t.x : `sqrt(x)sec(x^(3/2))*tan(x^(3/2))`


Integrate the following w.r.t.x : `(1)/(x^3 sqrt(x^2 - 1)`


Integrate the following w.r.t.x : log (x2 + 1)


Evaluate the following.

`int x^2 e^4x`dx


Evaluate the following.

`int "e"^"x" [(log "x")^2 + (2 log "x")/"x"]` dx


Choose the correct alternative from the following.

`int (1 - "x")^(-2) "dx"` = 


Evaluate: `int "dx"/(3 - 2"x" - "x"^2)`


Choose the correct alternative:

`int ("d"x)/((x - 8)(x + 7))` =


`int 1/x  "d"x` = ______ + c


State whether the following statement is True or False:

If `int((x - 1)"d"x)/((x + 1)(x - 2))` = A log|x + 1|  + B log|x – 2|, then A + B = 1


Evaluate `int 1/(4x^2 - 1)  "d"x`


`int "e"^x x/(x + 1)^2  "d"x`


∫ log x · (log x + 2) dx = ?


The value of `int "e"^(5x) (1/x - 1/(5x^2))  "d"x` is ______.


If u and v ore differentiable functions of x. then prove that:

`int uv  dx = u intv  dx - int [(du)/(d) intv  dx]dx`

Hence evaluate `intlog x  dx`


`int x/((x + 2)(x + 3)) dx` = ______ + `int 3/(x + 3) dx`


Find `int (sin^-1x)/(1 - x^2)^(3//2) dx`.


`intsqrt(1+x)  dx` = ______


`inte^(xloga).e^x dx` is ______


`int logx  dx = x(1+logx)+c`


Evaluate `int(1 + x + (x^2)/(2!))dx`


Evaluate:

`intcos^-1(sqrt(x))dx`


`int (sin^-1 sqrt(x) + cos^-1 sqrt(x))dx` = ______.


Prove that `int sqrt(x^2 - a^2)dx = x/2 sqrt(x^2 - a^2) - a^2/2 log(x + sqrt(x^2 - a^2)) + c`


The value of `int e^x((1 + sinx)/(1 + cosx))dx` is ______.


Evaluate:

`int x^2 cos x  dx`


Evaluate the following.

`intx^3/sqrt(1+x^4)`dx


Evaluate the following.

`intx^3/(sqrt(1 + x^4))dx`


Which expression is the integration-by-parts form for a product \(f(x)g(x)\)?


For \[\int \frac{x\sin^{-1}x}{\sqrt{1-x^2}}\,dx,\] which functions are chosen as the first function and the second function?


When applying integration by parts to \(\log x\) and inverse trig, what should they be multiplied by?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×