English

Choose the correct options from the given alternatives : ∫x-sinx1-cosx⋅dx =

Advertisements
Advertisements

Question

Choose the correct options from the given alternatives :

`int (x- sinx)/(1 - cosx)*dx` =

Options

  • `x cot (x/2) + c`

  • `- x cot (x/2) + c`

  • `cot (x/2) + c`

  • `x tan (x/2) + c`

MCQ
Advertisements

Solution

`- x cot (x/2) + c`

[ Hint : `int (x- sinx)/(1 - cosx)*dx = int (x - 2sin(x/2)cos(x/2))/(2sin^2 (x/2))*dx`

= `(1)/(2) int x"cosec"^2(x/2)*dx - int cot(x/2)*dx`

= `(1)/(2) [x int "cosec"^2 (x/2)*dx - int [d/dx(x) int "cosec"^2(x/2)^(dx)]*dx - int cot(x/2)*dx`

= `(1)/(2)[x{(-cot(x/2))/((1/2))} - int1* (-cot(x/2))/((1/2))*dx - intcot(x/2)*dx`

= `xcot(x/2) + int cot(x/2)*dx - int cot(x/2)*dx`

= `- x cot(x/2) + c`].

shaalaa.com
  Is there an error in this question or solution?
Chapter 3: Indefinite Integration - Miscellaneous Exercise 3 [Page 148]

APPEARS IN

Balbharati Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
Chapter 3 Indefinite Integration
Miscellaneous Exercise 3 | Q 1.06 | Page 148

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Evaluate `int_0^(pi)e^2x.sin(pi/4+x)dx`


Integrate the function in x log x.


Integrate the function in x log 2x.


Integrate the function in x sin−1 x.


Integrate the function in `((x- 3)e^x)/(x - 1)^3`.


`int e^x sec x (1 +   tan x) dx` equals:


Find : 

`∫(log x)^2 dx`


Evaluate the following : `int (t.sin^-1 t)/sqrt(1 - t^2).dt`


Evaluate the following : `int x.cos^3x.dx`


Integrate the following functions w.r.t. x : `sqrt(5x^2 + 3)`


Integrate the following functions w.r.t. x : `sec^2x.sqrt(tan^2x + tan x - 7)`


Integrate the following functions w.r.t. x : `sqrt(2x^2 + 3x + 4)`


Integrate the following functions w.r.t. x : `e^x .(1/x - 1/x^2)`


Integrate the following functions w.r.t. x : cosec (log x)[1 – cot (log x)] 


Choose the correct options from the given alternatives :

`int tan(sin^-1 x)*dx` =


Choose the correct options from the given alternatives :

`int [sin (log x) + cos (log x)]*dx` =


Evaluate the following.

∫ x log x dx


Evaluate the following.

`int "e"^"x" "x"/("x + 1")^2` dx


Evaluate the following.

`int [1/(log "x") - 1/(log "x")^2]` dx


Choose the correct alternative from the following.

`int (("x"^3 + 3"x"^2 + 3"x" + 1))/("x + 1")^5  "dx"` = 


Evaluate: `int "dx"/sqrt(4"x"^2 - 5)`


Evaluate: `int "dx"/("9x"^2 - 25)`


`int 1/sqrt(2x^2 - 5)  "d"x`


`int sqrt(tanx) + sqrt(cotx)  "d"x`


Choose the correct alternative:

`int ("d"x)/((x - 8)(x + 7))` =


Evaluate `int 1/(x(x - 1))  "d"x`


`int log x * [log ("e"x)]^-2` dx = ?


Evaluate the following:

`int_0^1 x log(1 + 2x)  "d"x`


If u and v ore differentiable functions of x. then prove that:

`int uv  dx = u intv  dx - int [(du)/(d) intv  dx]dx`

Hence evaluate `intlog x  dx`


`int 1/sqrt(x^2 - 9) dx` = ______.


State whether the following statement is true or false.

If `int (4e^x - 25)/(2e^x - 5)` dx = Ax – 3 log |2ex – 5| + c, where c is the constant of integration, then A = 5.


If `int(x + (cos^-1 3x)^2)/sqrt(1 - 9x^2)dx = 1/α(sqrt(1 - 9x^2) + (cos^-1 3x)^β) + C`, where C is constant of integration , then (α + 3β) is equal to ______.


`int((4e^x - 25)/(2e^x - 5))dx = Ax + B log(2e^x - 5) + c`, then ______.


`int1/sqrt(x^2 - a^2) dx` = ______


Evaluate the following.

`int x^3 e^(x^2) dx`


Evaluate: 

`int(1+logx)/(x(3+logx)(2+3logx))  dx`


`int(xe^x)/((1+x)^2)  dx` = ______


Evaluate:

`inte^x sinx  dx`


Evaluate the following.

`intx^3  e^(x^2) dx`


Evaluate the following.

`intx^3e^(x^2) dx`


If ∫(cot x – cosec2 x)ex dx = ex f(x) + c then f(x) will be ______.


Evaluate the following.

`intx^3/sqrt(1+x^4)`dx


Evaluate the following.

`intx^2e^(4x)dx`


The value of `inta^x.e^x dx` equals


Evaluate.

`int(5x^2 - 6x + 3)/(2x - 3)  dx`


The value of `int (x sin^-1)/(sqrt(1 - x^2)) dx` is equal to:


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×