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Choose the correct options from the given alternatives : ∫x-sinx1-cosx⋅dx =

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Question

Choose the correct options from the given alternatives :

`int (x- sinx)/(1 - cosx)*dx` =

Options

  • `x cot (x/2) + c`

  • `- x cot (x/2) + c`

  • `cot (x/2) + c`

  • `x tan (x/2) + c`

MCQ
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Solution

`- x cot (x/2) + c`

[ Hint : `int (x- sinx)/(1 - cosx)*dx = int (x - 2sin(x/2)cos(x/2))/(2sin^2 (x/2))*dx`

= `(1)/(2) int x"cosec"^2(x/2)*dx - int cot(x/2)*dx`

= `(1)/(2) [x int "cosec"^2 (x/2)*dx - int [d/dx(x) int "cosec"^2(x/2)^(dx)]*dx - int cot(x/2)*dx`

= `(1)/(2)[x{(-cot(x/2))/((1/2))} - int1* (-cot(x/2))/((1/2))*dx - intcot(x/2)*dx`

= `xcot(x/2) + int cot(x/2)*dx - int cot(x/2)*dx`

= `- x cot(x/2) + c`].

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Chapter 3: Indefinite Integration - Miscellaneous Exercise 3 [Page 148]

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Balbharati Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
Chapter 3 Indefinite Integration
Miscellaneous Exercise 3 | Q 1.06 | Page 148

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