English

Choose the correct alternative: ∫x23x3dx = - Mathematics and Statistics

Advertisements
Advertisements

Question

Choose the correct alternative:

`intx^(2)3^(x^3) "d"x` =

Options

  • `(3)^(x^3) + "c"`

  • `((3)^(x^3))/(3log3) + "c"`

  • `log 3*(3)^(x^3) + "c"`

  • `x^2 (3)^(x^2) + "c"`

MCQ
Advertisements

Solution

`((3)^(x^3))/(3log3) + "c"` 

shaalaa.com
  Is there an error in this question or solution?
Chapter 1.5: Integration - Q.1

RELATED QUESTIONS

Integrate the function in (sin-1x)2.


Integrate the function in tan-1 x.


Integrate the function in `e^x (1/x - 1/x^2)`.


Evaluate the following : `int x^3.tan^-1x.dx`


Evaluate the following : `int e^(2x).cos 3x.dx`


Evaluate the following: `int x.sin^-1 x.dx`


Evaluate the following:

`int x.sin 2x. cos 5x.dx`


Integrate the following functions w.r.t. x : `xsqrt(5 - 4x - x^2)`


Integrate the following w.r.t.x : `log (1 + cosx) - xtan(x/2)`


Integrate the following w.r.t.x : e2x sin x cos x


Choose the correct alternative from the following.

`int (("e"^"2x" + "e"^"-2x")/"e"^"x") "dx"` = 


Evaluate: `int "dx"/sqrt(4"x"^2 - 5)`


`int logx/(1 + logx)^2  "d"x`


The value of `int "e"^(5x) (1/x - 1/(5x^2))  "d"x` is ______.


Find `int_0^1 x(tan^-1x)  "d"x`


Evaluate the following:

`int ((cos 5x + cos 4x))/(1 - 2 cos 3x) "d"x`


Evaluate the following:

`int_0^pi x log sin x "d"x`


The value of `int_0^(pi/2) log ((4 + 3 sin x)/(4 + 3 cos x))  dx` is


`int 1/sqrt(x^2 - 9) dx` = ______.


If `int(2e^(5x) + e^(4x) - 4e^(3x) + 4e^(2x) + 2e^x)/((e^(2x) + 4)(e^(2x) - 1)^2)dx = tan^-1(e^x/a) - 1/(b(e^(2x) - 1)) + C`, where C is constant of integration, then value of a + b is equal to ______.


Find `int e^(cot^-1x) ((1 - x + x^2)/(1 + x^2))dx`.


Find `int (sin^-1x)/(1 - x^2)^(3//2) dx`.


Find: `int e^(x^2) (x^5 + 2x^3)dx`.


`int1/(x+sqrt(x))  dx` = ______


Solve the differential equation (x2 + y2) dx - 2xy dy = 0 by completing the following activity.

Solution: (x2 + y2) dx - 2xy dy = 0

∴ `dy/dx=(x^2+y^2)/(2xy)`                      ...(1)

Puty = vx

∴ `dy/dx=square`

∴ equation (1) becomes

`x(dv)/dx = square`

∴ `square  dv = dx/x`

On integrating, we get

`int(2v)/(1-v^2) dv =intdx/x`

∴ `-log|1-v^2|=log|x|+c_1`

∴ `log|x| + log|1-v^2|=logc       ...["where" - c_1 = log c]`

∴ x(1 - v2) = c

By putting the value of v, the general solution of the D.E. is `square`= cx


`inte^(xloga).e^x dx` is ______


If ∫(cot x – cosec2 x)ex dx = ex f(x) + c then f(x) will be ______.


Evaluate the following.

`intx^3/sqrt(1+x^4)`dx


The value of `inta^x.e^x dx` equals


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×