Advertisements
Advertisements
Question
DL and BM are the heights on sides AB and AD respectively of parallelogram ABCD (see the given figure). If the area of the parallelogram is 1470 cm2, AB = 35 cm and AD = 49 cm, find the length of BM and DL.
Advertisements
Solution
Area of parallelogram = Base × Height
= AB × DL
1470 = 35 × DL
DL = `1470/35`
DL = 42 cm
Also, area of parallelogram = AD × BM
1470 = 49 × BM
∴ BM = `1470/49`
∴ BM = 30 cm
APPEARS IN
RELATED QUESTIONS
Find the area of the following parallelogram:
PQRS is a parallelogram (see the given figure). QM is the height from Q to SR and QN is the height from Q to PS. If SR = 12 cm and QM = 7.6 cm. Find:
- the area of the parallelogram PQRS
- QN, if PS = 8 cm
If base of a parallelogram is 18 cm and its height is 11 cm, find its area.
Find the missing values.
| Base | Height | Area |
| 18 cm | 5 cm |
Find the area of the parallelogram ABCD if AC is 24 cm and BE = DF = 8 cm
Ratio of area of ∆MNO to the area of parallelogram MNOP in the same figure is ______.
In the following figure, EFGH is a parallelogram, altitudes FK and FI are 8 cm and 4 cm respectively. If EF = 10 cm, then area of EFGH is ______.
If perimeter of two parallelograms are equal, then their areas are also equal.
In the following figure, area of ∆AFB is equal to the area of parallelogram ABCD. If altitude EF is 16 cm long, find the altitude of the parallelogram to the base AB of length 10 cm. What is the area of ∆DAO, where O is the midpoint of DC?
ABCD is a parallelogram in which AE is perpendicular to CD (see figure). Also AC = 5 cm, DE = 4 cm and area of ΔAED = 6 cm2. Find the perimeter and area of ABCD.
