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Maharashtra State BoardSSC (English Medium) 10th Standard

Complete the Following Table.

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Question

Complete the following table.

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Solution

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Chapter 10: Space Missions - Exercise [Page 144]

RELATED QUESTIONS

Why are geostationary satellites not useful for studies of polar regions?


Solve the problem.

How much time a satellite in an orbit at height 35780 km above earth's surface would take, if the mass of the earth would have been four times its original mass?


Considering first correlation, complete the second.
Hubble telescope : At 569 km above the earth’s surface
Orbit of Hubble telescope : .............................


Mahendra and Virat are sitting at a distance of 1 metre from each other. Their masses are 75 kg and 80 kg respectively. What is the gravitational force between them? G = 6.67 x 10-11 Nm2/kg2 


The function of a satellite launcher is based on Newton's second law of motion.


Calculate the critical velocity of the satellite to be located at 35780 km above the surface of earth.


Distinguish between:

High Earth orbit - Medium Earth orbit.


Observe the figure and write the answers.

  1. Name the outer orbit.
  2. Which satellites revolve in low earth orbits?
  3. Which various orbits are given in the figure?
  4. Give an example of a launch vehicle based on Newton’s third law.

Note the relationship between the entries in all the three columns in the table and rewrite the table.

Column-1
(Location)
Column-2
Height from the earth’s surface (km)
Column-3
g (m/s2)
Earth’s surface (average) 8.8 0.225
Mount Everest 36.6 9.81
The highest height ever reached by man made balloon 400 9.8
Orbit of spacecraft 35700 9.77
Orbit of communication satellite 0 8.7

Define orbital velocity.


Write a note on orbital velocity


Why are some satellites called geostationary?


What is microgravity?


Give scientific reasons.

The geostationary satellite is not useful in the study of polar regions.


Geostationary satellites are not useful for studies of the polar region.


Calculate the time taken by a satellite for one revolution revolving at a height of 6400 km above the earth's surface with a velocity of 5.6 km/s.


The height of medium earth orbit above the surface of the earth is ______.


Complete the following equations:


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