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प्रश्न
Complete the following table.

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उत्तर

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संबंधित प्रश्न
Fill in the blank and explain the statement with reasoning:
If the height of the orbit of a satellite from the earth surface is increased, the tangential velocity of the satellite will ......
If the height of a satellite completing one revolution around the earth in T seconds is h1 meter, then what would be the height of a satellite taking \[2\sqrt{2} T\] seconds for one revolution?
Considering first correlation, complete the second.
Hubble telescope : At 569 km above the earth’s surface
Orbit of Hubble telescope : .............................
Mahendra and Virat are sitting at a distance of 1 metre from each other. Their masses are 75 kg and 80 kg respectively. What is the gravitational force between them? G = 6.67 x 10-11 Nm2/kg2
Write the proper name of the orbits of satellites shown in the following figure with their height from the earth’s surface.

Observe the figure and write the answers.

- Name the outer orbit.
- Which satellites revolve in low earth orbits?
- Which various orbits are given in the figure?
- Give an example of a launch vehicle based on Newton’s third law.
Define orbital velocity.
How is a satellite maintained in nearly circular orbit?
Why are some satellites called geostationary?
What is microgravity?
The orbital velocity of the satellite depends on its ______.
Give scientific reasons.
The geostationary satellite is not useful in the study of polar regions.
Geostationary satellites are not useful for studies of the polar region.
Complete the Following table.
| Sr. no. | Type of Satellite | The names of Indian Satellite and launcher |
| (1) | Navigational Satellite | Satellite: ______ |
| Launcher: ______ | ||
| (2) | Earth Observation Satellite | Satellite: ______ |
| Launcher: ______ |
Complete the following equations:

The orbit of a satellite is exactly 35780 km above the earth's surface and its tangential velocity is 3.08 km/s.
How much time the satellite will take to complete one revolution around the earth?
(Radius of earth = 6400 km.)
