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Question
Numerical problem.
Calculate the speed with which a satellite moves if it is at a height of 36,000 km from the Earth’s surface and has an orbital period of 24 hr (Take R = 6370 km) [Hint: Convert hr into seconds before doing calculation]
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Solution
T = `"2π(R+h)"/"v"`
86400 =` "2 × 3.14 × (6370 + 36000)"/"v"`
v = 6.28 × 42370
266083.6 km/sec
S = `"d"/"t"`
= `266083/24`
= 11086.79 km/h
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