Advertisements
Advertisements
Question
Numerical problem.
At an orbital height of 400 km, find the orbital period of the satellite.
Advertisements
Solution
h = 400 × 103m, R = 6371 × 103m,
v = 7616 × 103 kms– 1.
Substituting the values,
T = `"2π(R+h)"/"v"`
T = `6.28 × 6771/7616`
T = 5.583 × 103s = 5583 .
T ≈ 93 min
APPEARS IN
RELATED QUESTIONS
Why are geostationary satellites not useful for studies of polar regions?
Name the first artificial satellite sent by Russia in space.
A group of students from COEP Pune sent a small satellite _______ through ISRO in 2016.
Write functions of Military satellite and Navigational satellite.
Note the relationship between the entries in all the three columns in the table and rewrite the table.
| Column-1 (Location) |
Column-2 Height from the earth’s surface (km) |
Column-3 g (m/s2) |
| Earth’s surface (average) | 8.8 | 0.225 |
| Mount Everest | 36.6 | 9.81 |
| Maximum height ever reached by manmade balloon | 400 | 9.8 |
| Orbit of a typical weather satellite | 35700 | 9.77 |
| Orbit of communication satellite | 0 | 8.7 |
Numerical problem.
Calculate the speed with which a satellite moves if it is at a height of 36,000 km from the Earth’s surface and has an orbital period of 24 hr (Take R = 6370 km) [Hint: Convert hr into seconds before doing calculation]
Geostationary satellites are not useful for studies of the polar region.
The height of medium earth orbit above the surface of the earth is ______.
Write the name of small satellite made by a group of students from COEP (College of Engineering, Pune) sent to the space through ISRO in 2016.
The orbit of a satellite is exactly 35780 km above the earth's surface and its tangential velocity is 3.08 km/s.
How much time the satellite will take to complete one revolution around the earth?
(Radius of earth = 6400 km.)
