Advertisements
Advertisements
प्रश्न
Numerical problem.
At an orbital height of 400 km, find the orbital period of the satellite.
Advertisements
उत्तर
h = 400 × 103m, R = 6371 × 103m,
v = 7616 × 103 kms– 1.
Substituting the values,
T = `"2π(R+h)"/"v"`
T = `6.28 × 6771/7616`
T = 5.583 × 103s = 5583 .
T ≈ 93 min
APPEARS IN
संबंधित प्रश्न
Answer the question:
What is meant by the orbit of a satellite? On what basis and how are the orbits of artificial satellites classified?
Write the proper name of the orbits of satellites shown in the following figure with their height from the earth’s surface.
Write functions of Military satellite and Navigational satellite.
Note the relationship between the entries in all the three columns in the table and rewrite the table.
| Column-1 (Location) |
Column-2 Height from the earth’s surface (km) |
Column-3 g (m/s2) |
| Earth’s surface (average) | 8.8 | 0.225 |
| Mount Everest | 36.6 | 9.81 |
| Maximum height ever reached by manmade balloon | 400 | 9.8 |
| Orbit of a typical weather satellite | 35700 | 9.77 |
| Orbit of communication satellite | 0 | 8.7 |
Define orbital velocity.
Write a note on orbital velocity
Geostationary satellites are not useful for studies of the polar region.
The height of medium earth orbit above the surface of the earth is ______.
Complete the following equations:
The orbit of a satellite is exactly 35780 km above the earth's surface and its tangential velocity is 3.08 km/s.
How much time the satellite will take to complete one revolution around the earth?
(Radius of earth = 6400 km.)
