Advertisements
Advertisements
प्रश्न
Numerical problem.
Calculate the speed with which a satellite moves if it is at a height of 36,000 km from the Earth’s surface and has an orbital period of 24 hr (Take R = 6370 km) [Hint: Convert hr into seconds before doing calculation]
Advertisements
उत्तर
T = `"2π(R+h)"/"v"`
86400 =` "2 × 3.14 × (6370 + 36000)"/"v"`
v = 6.28 × 42370
266083.6 km/sec
S = `"d"/"t"`
= `266083/24`
= 11086.79 km/h
APPEARS IN
संबंधित प्रश्न
What is meant by the orbit of a satellite?
Why are geostationary satellites not useful for studies of polar regions?
Write functions of Military satellite and Navigational satellite.
Write a note on orbital velocity
How is a satellite maintained in nearly circular orbit?
Write down the formula of orbital velocity.
Give scientific reasons.
The geostationary satellite is not useful in the study of polar regions.
Complete the Following table.
| Sr. no. | Type of Satellite | The names of Indian Satellite and launcher |
| (1) | Navigational Satellite | Satellite: ______ |
| Launcher: ______ | ||
| (2) | Earth Observation Satellite | Satellite: ______ |
| Launcher: ______ |
Complete the following equations:
The orbit of a satellite is exactly 35780 km above the earth's surface and its tangential velocity is 3.08 km/s.
How much time the satellite will take to complete one revolution around the earth?
(Radius of earth = 6400 km.)
