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प्रश्न
Mahendra and Virat are sitting at a distance of 1 metre from each other. Their masses are 75 kg and 80 kg respectively. What is the gravitational force between them? G = 6.67 x 10-11 Nm2/kg2
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उत्तर
Given : r = 1 m, m1 = 75 kg, m2 = 80 kg
and G = 6.67 x 10 -11 Nm2/kg2
According to Newton’s law
`F = (Gm_1m_2)/(r^2)`
`F=(6.67 xx 10^(-11) xx 75 xx80)/1^2 n`
` = 4.002 xx 10^-7 N`
The gravitational force between Mahendra and Virat is 4.002 x 10-7 N
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