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Questions
Complete the following equations:
Complete the following chart:
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Solution
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RELATED QUESTIONS
Complete the following table.
Solve the problem.
How much time a satellite in an orbit at height 35780 km above earth's surface would take, if the mass of the earth would have been four times its original mass?
Considering first correlation, complete the second.
Hubble telescope : At 569 km above the earth’s surface
Orbit of Hubble telescope : .............................
Write the proper name of the orbits of satellites shown in the following figure with their height from the earth’s surface.
A group of students from COEP Pune sent a small satellite _______ through ISRO in 2016.
Distinguish between:
High Earth orbit - Medium Earth orbit.
Write functions of Military satellite and Navigational satellite.
Note the relationship between the entries in all the three columns in the table and rewrite the table.
| Column-1 (Location) |
Column-2 Height from the earth’s surface (km) |
Column-3 g (m/s2) |
| Earth’s surface (average) | 8.8 | 0.225 |
| Mount Everest | 36.6 | 9.81 |
| The highest height ever reached by man made balloon | 400 | 9.8 |
| Orbit of spacecraft | 35700 | 9.77 |
| Orbit of communication satellite | 0 | 8.7 |
Define orbital velocity.
How is a satellite maintained in nearly circular orbit?
Numerical problem.
Calculate the speed with which a satellite moves if it is at a height of 36,000 km from the Earth’s surface and has an orbital period of 24 hr (Take R = 6370 km) [Hint: Convert hr into seconds before doing calculation]
Numerical problem.
At an orbital height of 400 km, find the orbital period of the satellite.
What is microgravity?
The orbital velocity of the satellite depends on its ______.
The height of medium earth orbit above the surface of the earth is ______.
Write the name of small satellite made by a group of students from COEP (College of Engineering, Pune) sent to the space through ISRO in 2016.
The orbit of a satellite is exactly 35780 km above the earth's surface and its tangential velocity is 3.08 km/s.
How much time the satellite will take to complete one revolution around the earth?
(Radius of earth = 6400 km.)
