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Question
Calculate the time taken by a satellite for one revolution revolving at a height of 6400 km above the earth's surface with a velocity of 5.6 km/s.
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Solution
Given: Height of satellite (h) = 6400 km = 6.4 × 106 m
Velocity of satellite (Vc) = 5.6 km/s = 5.6 × 103 m/s
To find: Time taken for one revolution (T)
Formula: T = `(2π("R" + "h"))/"V"_"c"`
Calculation: T = `(2 xx 3.14 (6.4 xx 10^6 + 6.4 xx 10^6))/(5.6 xx 10^3)`
T = 14354 s ≈ 4 hours
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