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Check the injectivity and surjectivity of the following function: f : Z → Z given by f(x) = x^3

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Question

Check the injectivity and surjectivity of the following function:

f : Z → Z given by f(x) = x3

Sum
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Solution

f : Z → Z given by f(x) = x3

It is seen that for x, y ∈ Z, f(x) = f(y)

⇒ x3 = y3 

⇒ x = y

∴ f is injective.

Now, 2 ∈ Z, but there does not exist any element x ∈ Z such that f(x) = x3 = 2.

∴ f is not surjective.

Hence, function f is injective but not surjective.

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Chapter 1: Relations and Functions - EXERCISE 1.2 [Page 10]

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NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 1 Relations and Functions
EXERCISE 1.2 | Q 2. (v) | Page 10

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