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Let A = {A, B, C}, B = {U V, W} and Let F And G Be Two Functions From A To B And From B To A, Respectively, Defined as : F = {(A, V), (B, U), (C, W)}, G = {(U, B), (V, A), (W, C)}.Show that

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Question

Let A = {abc}, B = {u vw} and let f and g be two functions from A to B and from B to A, respectively, defined as :
f = {(av), (bu), (cw)}, g = {(ub), (va), (wc)}.
Show that f and g both are bijections and find fog and gof.

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Solution

Proving f is a bijection :
f = {(av), (bu), (cw)} and : A → B
Injectivity of f: No two elements of have the same image in B.
So, f is one-one.
Surjectivity of f: Co-domain of f = {u vw}
Range of = {u vw}
Both are same.
So,  f is onto.
Hence, f is a bijection.

Proving is a bijection :
g = {(ub), (va), (wc)} and B → A
Injectivity of g: No two elements of B  have the same image in A.
So, g is one-one.
Surjectivity of g: Co-domain of g = {abc}
Range of g = {abc}
Both are the same.
So, g is onto.
Hence, g is a bijection.

Finding  fog :
Co-domain of g is same as the domain of f.
So, fog exists and fog : {u vw→ {u vw}

(fog) (u (g (u)f (bu

(fog) (vf (g (v)f (av

(fog) (wf (g (w)f (cw

So, fog (u, u)(v, v)(w, w}

Finding gof :
Co-domain of f is same as the domain of g.
So, fog exists and gof : {abc→ {abc}

(gof) (ag (f (a)g (va

(gof (bg (f (b)g (ub

(gof) (cg (f (c)g (wc

So, go(a, a), (b, b), (c, c}

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Chapter 2: Functions - Exercise 2.2 [Page 46]

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R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 2 Functions
Exercise 2.2 | Q 4 | Page 46

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