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Check the injectivity and surjectivity of the following function: f : Z → Z given by f(x) = x^2

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Question

Check the injectivity and surjectivity of the following function:

f : Z → Z given by f(x) = x2

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Solution

f : Z → Z given by f(x) = x2

Here, Z = {0, ±1, ±2, ±3, ....}

Injectivity:

Suppose f(–1) = f(1) = 1

But –1 ≠ 1

∴ f is not a one-one function.

Surjective:

There are many elements in a codomain Z which have no pre-image in the domain Z.

For example, 2 ∈ Z is an element of a codomain, but for f(x) = x2 there is no x ∈ Z such that f(x) = 2, because `sqrt2` is not an integer.

∴ f is not onto.

Hence, f is neither injective nor surjective.

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Chapter 1: Relations and Functions - EXERCISE 1.2 [Page 10]

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NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 1 Relations and Functions
EXERCISE 1.2 | Q 2. (ii) | Page 10

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