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An Ac Circuit Consists of a Series Combination of Circuit Elements X and Y. the Current is Ahead of the Voltage in Phase by π 4 . If Element X is a Pure Resistor of 100ω ,

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Question

An ac circuit consists of a series combination of circuit elements X and Y. The current is ahead of the voltage  in phase by `pi /4` . If element X is a pure resistor of 100Ω ,

(a)  name the circuit element Y.
(b)  calculate the rms value of current, if rms value of voltage is  141V.
(c)  what will happen if the ac source is replaced by a dc source ?

Numerical
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Solution

(a) Since current is leading voltage by `pi/4`, current leak in capacitive curcuit as X is pure resistor therefore Y capacitor.

(b) `phi = tan ^(-1) ((X_c - X_L)/R) X_L = 0`

`pi/4 = tan^(-1)((X_c)/R)` 

`(X_c)/R= tan  pi/4`              

  

`(X_c)/R= 1`                      Xc = R 

                                       Xc = 100 Ω  

`t = sqrt((100)^2 + (100)^2)`

`t = 100 sqrt(2) Omega = 100 xx 1.41 = 141  Omega `

`i_(RMS) = (e_(RMS))/z = 141/141 = 1A`

iRMS = 1A 

(c) If we replace ac source by dc ω = 0

`X_c = 1/(omega _c)`

`X_c = 1/0 = ∞  Omega` 

`i = e/z = 141/ ∞  `

i = 0

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2018-2019 (March) 55/3/3

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