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A train moving with a velocity of 20 ms−1 is brought to rest by applying brakes in 5 s. Calculate the retardation. - Physics

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Question

A train moving with a velocity of 20 ms−1 is brought to rest by applying brakes in 5 s. Calculate the retardation.

Numerical
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Solution

Given:

  • Initial velocity, u = 20 m/s

  • Final velocity, v = 0 m/s (since train comes to rest)

  • Time, t = 5 s

0 = 20 + a × 5

0 = 20 + 5a

5a = −20

a = −4m/s2

Retardation = 4 m/s2

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Chapter 2: Motion in One Dimension - Exercise 2 (C) [Page 54]

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Selina Concise Physics [English] Class 9 ICSE
Chapter 2 Motion in One Dimension
Exercise 2 (C) | Q 6 | Page 54
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