Advertisements
Advertisements
Question
A train moving with a velocity of 20 ms−1 is brought to rest by applying brakes in 5 s. Calculate the retardation.
Advertisements
Solution
Given:
-
Initial velocity, u = 20 m/s
-
Final velocity, v = 0 m/s (since train comes to rest)
-
Time, t = 5 s
0 = 20 + a × 5
0 = 20 + 5a
5a = −20
a = −4m/s2
Retardation = 4 m/s2
APPEARS IN
RELATED QUESTIONS
A motor bike running at 5 ms−1, picks up a velocity of 30 ms−1 in 5s. Calculate
- acceleration
- distance covered during acceleration.
The acceleration of a body is 8.5 ms-2. What does this statement mean?
Write the SI unit of retardation.
State if the following situation is possible:
A body moving with a constant velocity in an accelerated motion.
A body has an acceleration of -3.5 ms-2. What is its retardation?
A car accelerates uniformly from a velocity of 18 km/h to 36 km/h in 15 min. What is its acceleration?
The graph shows how the velocity of a scooter varies with time in 50 s.
Work out: Deceleration
The slope of a velocity-time graph gives ______.
m/s2 is the unit of ______.
A car is being driven at a speed of 20ms-1 when brakes are applied to bring it to rest in 5 s. The deceleration produced in this case will be ______.
