Advertisements
Advertisements
प्रश्न
A train moving with a velocity of 20 ms−1 is brought to rest by applying brakes in 5 s. Calculate the retardation.
Advertisements
उत्तर
Given:
-
Initial velocity, u = 20 m/s
-
Final velocity, v = 0 m/s (since train comes to rest)
-
Time, t = 5 s
0 = 20 + a × 5
0 = 20 + 5a
5a = −20
a = −4m/s2
Retardation = 4 m/s2
APPEARS IN
संबंधित प्रश्न
Give a scientific reason.
When an object falls freely to the ground, its acceleration is uniform.
Define acceleration. State its unit.
Figure shows the velocity-time graphs for two cars A and B moving in the same direction. Which car has greater acceleration? Give reasons to your answer.

A train starts from rest and accelerates uniformly at a rate of 2 m s−2 for 10 s. It then maintains a constant speed for 200 s. The brakes are then applied and the train is uniformly retarded and comes to rest in 50 s. Find
- The maximum velocity reached,
- The retardation in the last 50 s,
- The total distance travelled,
- The average velocity of the train.
An aeroplane lands at 216 kmh−1 and stops after covering a runway of 2 m. Calculate the acceleration and the time, in which it comes to rest.
A body falls towards the earth. Does it have positive or negative acceleration?
Write the SI unit of acceleration and retardation.
Interpret the following graph:
Convert the following acceleration:
1/36 m/s2 into km/h2
The rate of change of velocity is ______.
