Advertisements
Advertisements
प्रश्न
The change in velocity of a motorbike is 54 kmh−1 in one minute. Calculate its acceleration in (a) ms−2 (b) kmh−2.
Advertisements
उत्तर
Change in velocity = 54 kmh−1 = `54xx1000/3600` ms−1 = 15 ms−1
Time = 1 minute = 60 s
Acceleration (a) = `"Change in velocity"/"Time"`
= `15/60` ms−2
a = 0.25 ms−2
a = `0.25xx1000/3600xx3600` kmh−2 = 3240 kmh−2
APPEARS IN
संबंधित प्रश्न
Define acceleration. State its unit.
Figure shows the velocity-time graphs for two cars A and B moving in the same direction. Which car has greater acceleration? Give reasons to your answer.
A body falls freely from a certain height. Show graphically the relation between the distance fallen and square of time. How will you determine g from this graph?
A space craft flying in a straight course with velocity of 75 km s-1 fires its rocket motors for 6.0 s. At the end of this time its speed is 120 km s-1 in the same direction.
Find
(i) The space craft's average acceleration while the motors were firing
(ii) The distance travelled by the space craft in the first 10 s after the rocket motors were started, the motors being in action for only 6 s.
A car travels with uniform velocity of 25 m s-1 for 5 s. The brakes are then applied and the car is uniformly retarded and comes to rest in further 10 s. Find:
- The distance which the car travels before the brakes are applied,
- Retardation and
- The distance travelled by car after applying the brakes.
From the diagram given below, calculate acceleration.
A motorbike, initially at rest, picks up a velocity of 72 kmh−1 over a distance of 40 m. Calculate
- acceleration
- time in which it picks up above velocity.
If the velocity of a body does not change, then its acceleration is ______.
When a body starts from rest, the acceleration of the body after 2 seconds in ______ of its displacement.
An object can be moving with uniform speed but with variable acceleration.
