Advertisements
Advertisements
Question
The change in velocity of a motorbike is 54 kmh−1 in one minute. Calculate its acceleration in (a) ms−2 (b) kmh−2.
Advertisements
Solution
Change in velocity = 54 kmh−1 = `54xx1000/3600` ms−1 = 15 ms−1
Time = 1 minute = 60 s
Acceleration (a) = `"Change in velocity"/"Time"`
= `15/60` ms−2
a = 0.25 ms−2
a = `0.25xx1000/3600xx3600` kmh−2 = 3240 kmh−2
APPEARS IN
RELATED QUESTIONS
Give a scientific reason.
When an object falls freely to the ground, its acceleration is uniform.
State the type of motion represented by the following sketches in Figures.
Give an example of each type of motion.
A car travels with uniform velocity of 25 m s-1 for 5 s. The brakes are then applied and the car is uniformly retarded and comes to rest in further 10 s. Find:
- The distance which the car travels before the brakes are applied,
- Retardation and
- The distance travelled by car after applying the brakes.
Draw velocity – time graph for the following situation:
When a body is moving with variable velocity, but uniform retardation.
From the velocity – time graph given below, calculate deceleration in region BC.
Diagram is given below shows velocity – time graph of car P and Q, starting from the same place and in the same direction. Calculate the Acceleration of car P.
A motor bike running at 90 kmh−1 is slowed down to 18 kmh−1 in 2.5 s. Calculate
- acceleration
- distance covered during slow down.
The initial velocity of a car is 10 ms-1. It moves with an acceleration of 2 ms-2. What will be its speed after 10 seconds?
Assertion: The accelerated motion of an object may be due to change in magnitude of velocity or direction or both of them.
Reason: Acceleration can be produced only by change in magnitude of the velocity. It does not depend the direction.
Assertion: When a body is subjected to a uniform acceleration, it is always moving in a straight line.
Reason: Motion may be straight-line motion or circular motion.
