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Questions
A reaction is first order in A and second order in B. How is the rate affected when the concentrations of both A and B are doubled?
A reaction is of first order with respect to reactant [A] and second order with regard to reactant [B]. What is the effect on rate of reaction when concentrations of both [A] and [B] are doubled?
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Solution
When the concentrations of both A and B are doubled,
Rate = k(2a) (2b)2
= k(2a) (4b2)
= 8 kab2
∴ The reaction rate will increase by a factor of 8.
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