Question

At concentration of 0.1 and 0.2 mol L^–1 the rates of deem position of a compound were found to be 0.18 and 0.72 mol L^–1 m^–1. What is the order of the reaction?

Options

• 2

• 1

• 3

• 4

Answer 1

2

Explanation:

Rate of reaction= K[A]n

Where n = order of the reaction

According to available data,

(rate)1 = 0.18 mol L^–1 min^–1, C1 = 0.1 mol L^–1

(rate)2 = 0.72 mol L^–1 min^–1, C2 = 0.2 mol L^–1

`(rate)_2/(rate)_1 = (K(C_2)n)/(K(C_1)n)` or

`(0.72  "mol"^-1 "min"^-1)/(0.18  "mol"^-1 "min"^-1) = (K(0.2  "mol"  L^-1)^n)/(K(0.1  "mol"  L^-1)^n)`

4 or (2)² = 2n or n = 2 or

Order of reaction = 2