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Question
A motorcycle moving with a speed of 5 m/s is subjected to an acceleration of 0.2 m/s2. Calculate the speed of the motorcycle after 10 seconds, and the distance travelled in this time.
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Solution
We have to find the distance travelled and final velocity of the body. We have the following information given,
Initial velocity, (u) = 5 m/s
Acceleration, (a) = 0.2 m/s2
Time taken, (t) = 10 s
So, we can find the final velocity using the relation,
v = u + at
So, final velocity,
v = 5 + (0.2)(10)
= 7 m/s
We can calculate the distance travelled by using the 2nd equation of motion,
`s = ut + 1/2 at^2`
Put the values in above equation to find the distance travelled by the motorcycle ,
`(s) = 5(10) + 1/2(0.2)(10)^2`
= (50 + 10) m
= 60 m
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