Advertisements
Advertisements
प्रश्न
A motorcycle moving with a speed of 5 m/s is subjected to an acceleration of 0.2 m/s2. Calculate the speed of the motorcycle after 10 seconds, and the distance travelled in this time.
Advertisements
उत्तर
We have to find the distance travelled and final velocity of the body. We have the following information given,
Initial velocity, (u) = 5 m/s
Acceleration, (a) = 0.2 m/s2
Time taken, (t) = 10 s
So, we can find the final velocity using the relation,
v = u + at
So, final velocity,
v = 5 + (0.2)(10)
= 7 m/s
We can calculate the distance travelled by using the 2nd equation of motion,
`s = ut + 1/2 at^2`
Put the values in above equation to find the distance travelled by the motorcycle ,
`(s) = 5(10) + 1/2(0.2)(10)^2`
= (50 + 10) m
= 60 m
APPEARS IN
संबंधित प्रश्न
Which of the two can be zero under certain conditions : average speed of a moving body or average velocity of a moving body ?
Explain why, the motion of a body which is moving with constant speed in a circular path is said to be accelerated.
Explain the meaning of the following equation of motion :v = u + at, where symbols have their usual meanings.
The slope of a speed-time graph gives:
Write three equations of uniformly accelerated motion relating the initial velocity (u), final velocity (v), time (t), acceleration (a) and displacement (S).
A body, initially at rest, starts moving with a constant acceleration 2 m s-2. Calculate: (i) the velocity acquired and (ii) the distance travelled in 5 s.
Can you suggest a real-life example about the motion of a body from the following velocity – time graph?
A body is thrown vertically upward with velocity u, the greatest height h to which it will rise is,
The velocity-time graph (Fig. 8.5) shows the motion of a cyclist. Find (i) its acceleration (ii) its velocity and (iii) the distance covered by the cyclist in 15 seconds.
An object starting from rest travels 20 m in the first 2 s and 160 m in the next 4 s. What will be the velocity after 7 s from the start?
