Advertisements
Advertisements
प्रश्न
The velocity-time graph (Fig. 8.5) shows the motion of a cyclist. Find (i) its acceleration (ii) its velocity and (iii) the distance covered by the cyclist in 15 seconds.
Advertisements
उत्तर
Velocity-time graph is a straight line parallel to the time axis, so, the velocity of the cyclist is constant.
(i) Acceleration = 0
(ii) At, f = 15 s velocity = 20 m s’1 (from the given graph)
(iii) Distance covered by the cyclist in 15 s
= Area under v - t graph during that time interval
= 20 ms’1 x 15 s
= 300 m.
APPEARS IN
संबंधित प्रश्न
Fill in the following blank with a suitable word:
Acceleration is the rate of change of ______ It is measured in ______
A bus running at a speed of 18 km/h is stopped in 2.5 seconds by applying brakes. Calculate the retardation produced.
A body, initially at rest, starts moving with a constant acceleration 2 m s-2. Calculate: (i) the velocity acquired and (ii) the distance travelled in 5 s.
What do you understand by the term acceleration?
Multiple choice Question. Select the correct option.
A body dropped from the top of a tower reaches the ground in 4s. Height of the tower is
How can you find the following?
Acceleration from velocity – time graph.
Can you suggest a real-life example about the motion of a body from the following velocity – time graph?
A body is thrown vertically upward with velocity u, the greatest height h to which it will rise is,
A girl walks along a straight path to drop a letter in the letterbox and comes back to her initial position. Her displacement–time graph is shown in Fig.8.4. Plot a velocity-time graph for the same.
An electron moving with a velocity of 5 × 104 ms−1 enters into a uniform electric field and acquires a uniform acceleration of 104 ms–2 in the direction of its initial motion.
(i) Calculate the time in which the electron would acquire a velocity double of its initial velocity.
(ii) How much distance the electron would cover at this time?
