मराठी

The velocity-time graph (Fig. 8.5) shows the motion of a cyclist. Find (i) its acceleration (ii) its velocity and (iii) the distance covered by the cyclist in 15 seconds. - Science

Advertisements
Advertisements

प्रश्न

The velocity-time graph (Fig. 8.5) shows the motion of a cyclist. Find (i) its acceleration (ii) its velocity and (iii) the distance covered by the cyclist in 15 seconds.

थोडक्यात उत्तर
Advertisements

उत्तर

Velocity-time graph is a straight line parallel to the time axis, so, the velocity of the cyclist is constant.

(i) Acceleration = 0

(ii) At, f = 15 s velocity = 20 m s’1 (from the given graph)

(iii) Distance covered by the cyclist in 15 s

= Area under v - t graph during that time interval

= 20 ms’1 x 15 s

= 300 m.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 8: Motion - Short Answer Questions [पृष्ठ ५९]

APPEARS IN

एनसीईआरटी एक्झांप्लर Science [English] Class 9
पाठ 8 Motion
Short Answer Questions | Q 17. | पृष्ठ ५९

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Find the initial velocity of a car which is stopped in 10 seconds by applying brakes. The retardation due to brakes is 2.5 m/s2.


A body starting from rest travels with uniform acceleration. If it travels 100 m in 5 s, what is the value of acceleration ?


Derive the following equations for uniformly accelerated motion: 

(i) v = u + at 

(ii) `"S = ut" + 1/2 "at"^2`

(iii) v2 = u2 + 2aS

where the symbols have their usual meanings.


A body, initially at rest, starts moving with a constant acceleration 2 m s-2. Calculate: (i) the velocity acquired and (ii) the distance travelled in 5 s.


What do you understand by the term acceleration?


A packet is dropped from a stationary helicopter, hovering at a height ‘h’ from ground level, reaches the ground in 12s. Calculate

  1. the value of h
  2. final velocity of packet on reaching the ground. (Take g = 9.8 ms−2)

How will the equations of motion for an object moving with a uniform velocity change?


A girl walks along a straight path to drop a letter in the letterbox and comes back to her initial position. Her displacement–time graph is shown in Fig.8.4. Plot a velocity-time graph for the same.


An electron moving with a velocity of 5 × 104 ms−1 enters into a uniform electric field and acquires a uniform acceleration of 104 ms–2 in the direction of its initial motion.

(i) Calculate the time in which the electron would acquire a velocity double of its initial velocity.

(ii) How much distance the electron would cover at this time?


When will you say a body is at uniform acceleration?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×