Advertisements
Advertisements
प्रश्न
Multiple choice Question. Select the correct option.
A body dropped from the top of a tower reaches the ground in 4s. Height of the tower is
पर्याय
39.2 m
44.1 m
58.8 m
78.4 m
Advertisements
उत्तर
78.4 m
Explanation:
Initial velocity = u = 0
Time = t = 4s
As body falls downards,
so acceleration = a = + g = a = + 9.8 ms−2
(Distance) S = ut + 1/2 at
S = (0) (4) + 1/2 × 9.8 × (4)3
s = 0 + 1/2 × 9.8 × 16
S = 9.8 × 8 = 78.4 m
APPEARS IN
संबंधित प्रश्न
When will you say a body is at non-uniform acceleration?
A train starting from a railway station and moving with uniform acceleration attains a speed 40 km h−1 in 10 minutes. Find its acceleration.
A cheetah starts from, rest, and accelerates at 2 m/s2 for 10 seconds. Calculate :
(a) the final velocity
(b) the distance travelled.
Derive the formula : v = u + at, where the symbols have usual meanings.
When a car driver travelling at a speed of 10 m/s applies brakes and brings the car to rest in 20 s, then retardation will be :
The slope of a speed-time graph gives:
A car starting from rest acquires a velocity 180m s-1 in 0.05 h. Find the acceleration.
The velocity-time graph of a body in motion is a straight line inclined to the time axis. The correct statement is ___________
Can you suggest a real-life example about the motion of a body from the following velocity – time graph?
Two stones are thrown vertically upwards simultaneously with their initial velocities u1 and u2 respectively. Prove that the heights reached by them would be in the ratio of `"u"_1^2 : "u"_2^2` (Assume upward acceleration is –g and downward acceleration to be +g)
