Advertisements
Advertisements
प्रश्न
Multiple choice Question. Select the correct option.
A body dropped from the top of a tower reaches the ground in 4s. Height of the tower is
विकल्प
39.2 m
44.1 m
58.8 m
78.4 m
Advertisements
उत्तर
78.4 m
Explanation:
Initial velocity = u = 0
Time = t = 4s
As body falls downards,
so acceleration = a = + g = a = + 9.8 ms−2
(Distance) S = ut + 1/2 at
S = (0) (4) + 1/2 × 9.8 × (4)3
s = 0 + 1/2 × 9.8 × 16
S = 9.8 × 8 = 78.4 m
APPEARS IN
संबंधित प्रश्न
A train starting from a railway station and moving with uniform acceleration attains a speed 40 km h−1 in 10 minutes. Find its acceleration.
Which of the two can be zero under certain conditions : average speed of a moving body or average velocity of a moving body ?
Give one example of a situation in which a body has a certain average speed but its average velocity is zero.
What is meant by the term acceleration ? State the SI unit of acceleration.
A bus was moving with a speed of 54 km/h. On applying brakes it stopped in 8 seconds. Calculate the acceleration.
A car acquire a velocity of 72 km per hour in 10 second starting from rest. Find
(1) the acceleration,
(2) the average velocity, and
(3) the distance travelled in this time.
A car is travelling along the road at 8 ms-1. It accelerates at 1 ms-2 for a distance of 18 m. How fast is it then travelling ?
Which of the following could not be a unit of acceleration?
Can you suggest a real-life example about the motion of a body from the following velocity – time graph?

Two stones are thrown vertically upwards simultaneously with their initial velocities u1 and u2 respectively. Prove that the heights reached by them would be in the ratio of `"u"_1^2 : "u"_2^2` (Assume upward acceleration is –g and downward acceleration to be +g)
