Question

A car is travelling along the road at 8 ms^-1. It accelerates at 1 ms^-2 for a distance of 18 m. How fast is it then travelling ?

Answer 1

We have to find the final velocity of the moving object. And we have the following information
Initial velocity, (u) = 8 m/s
Acceleration, (a) = 1 m/s²
Distance, (s) = 18 m
So applying 3^rd equation of motion to calculate the final velocity,
`ν = sqrt(u^2 + 2as)`
Where,
(a) - Acceleration
(ν) - Final velocity
(u) - Initial velocity
(s) - Distance
Put the values in the above equation to get the value of final velocity,
`ν = sqrt(64 + 36)` m/s
= `sqrt(100)` m/s
= 10 m/s