Advertisements
Advertisements
प्रश्न
A car is travelling along the road at 8 ms-1. It accelerates at 1 ms-2 for a distance of 18 m. How fast is it then travelling ?
Advertisements
उत्तर
We have to find the final velocity of the moving object. And we have the following information
Initial velocity, (u) = 8 m/s
Acceleration, (a) = 1 m/s2
Distance, (s) = 18 m
So applying 3rd equation of motion to calculate the final velocity,
`ν = sqrt(u^2 + 2as)`
Where,
(a) - Acceleration
(ν) - Final velocity
(u) - Initial velocity
(s) - Distance
Put the values in the above equation to get the value of final velocity,
`ν = sqrt(64 + 36)` m/s
= `sqrt(100)` m/s
= 10 m/s
APPEARS IN
संबंधित प्रश्न
Name the physical quantity whose SI unit is :
(a) m/s (b) m/s2
Fill in the following blank with suitable word :
Velocity is the rate of change of……………………… It is measured in.............. .
Explain why, the motion of a body which is moving with constant speed in a circular path is said to be accelerated.
Find the initial velocity of a car which is stopped in 10 seconds by applying brakes. The retardation due to brakes is 2.5 m/s2.
A bicycle initially moving with a velocity 5.0 m s-1 accelerates for 5 s at a rate of 2 m s-2. What will be its final velocity?
Derive the following equations for uniformly accelerated motion:
(i) v = u + at
(ii) `"S = ut" + 1/2 "at"^2`
(iii) v2 = u2 + 2aS
where the symbols have their usual meanings.
What do you understand by the term acceleration?
Multiple choice Question. Select the correct option.
The speed of a car reduces from 15 m/s to 5 m/s over a displacement of 10 m. The uniform acceleration of the car is :
How can you find the following?
Acceleration from velocity – time graph.
Can you suggest a real-life example about the motion of a body from the following velocity – time graph?
