Advertisements
Advertisements
प्रश्न
A bus was moving with a speed of 54 km/h. On applying brakes it stopped in 8 seconds. Calculate the acceleration.
Advertisements
उत्तर
(b) We have to find the value of uniform acceleration. So, Initial velocity
(u) = 54 km/hr
= `"54(1000)"/3600` m/s
= 15 m/s
Final velocity (v) = 0 m/s
Time taken(t) = 8 s
So acceleration, `a = (v-u)/t`
Put the values in the above equation to get the value of acceleration
`a = (0-15)/8`
= -`1.875 "m/s"^2`
APPEARS IN
संबंधित प्रश्न
A bus decreases its speed from 80 km h−1 to 60 km h−1 in 5 s. Find the acceleration of the bus.
Fill in the following blank with a suitable word:
Acceleration is the rate of change of ______ It is measured in ______
What conclusion can you draw about the velocity of a body from the displacement-time graph shown below :

A car is travelling along the road at 8 ms-1. It accelerates at 1 ms-2 for a distance of 18 m. How fast is it then travelling ?
Give one example of following motion :
Variable acceleration
The velocity-time graph of a body in motion is a straight line inclined to the time axis. The correct statement is ___________
For a uniformly retarded motion, the velocity-time graph is _____________
Can you suggest a real-life example about the motion of a body from the following velocity – time graph?

Area under a v – t graph represents a physical quantity which has the unit
Two stones are thrown vertically upwards simultaneously with their initial velocities u1 and u2 respectively. Prove that the heights reached by them would be in the ratio of `"u"_1^2 : "u"_2^2` (Assume upward acceleration is –g and downward acceleration to be +g)
