Advertisements
Advertisements
प्रश्न
Describe the motion of a body which is accelerating at a constant rate of 10 m s–2. If the body starts from rest, how much distance will it cover in 2 s ?
Advertisements
उत्तर
We have to find the distance travelled by the body. We have the following information given,
So, Initial velocity, (u) = 0 m/s
Acceleration, (a) = 10 m/s2
Time taken, (t) = 2 s
We can calculate the distance travelled by using the 2nd equation of motion,
`s = ut + 1/2 at^2`
Put the values in above equation to find the distance travelled by the body,
`(s) = 0(2) + 1/2(10)(2)^2`
= 20 m
APPEARS IN
संबंधित प्रश्न
When will you say a body is at non-uniform acceleration?
Which of the two can be zero under certain conditions : average speed of a moving body or average velocity of a moving body ?
What term is used to denote the change of velocity with time ?
A freely falling object travels 4.9 m in 1st second, 14.7 m in 2 nd second, 24.5 m in 3rd second, and so on. This data shows that the motion of a freely falling object is a case of :
A bus increases its speed from 36 km/h to 72 km/h in 10 seconds. Its acceleration is :
How can you find the following?
Velocity from acceleration – time graph.
Can you suggest a real-life example about the motion of a body from the following velocity – time graph?
Can you suggest a real-life example about the motion of a body from the following velocity – time graph?
Can you suggest a real-life example about the motion of a body from the following velocity – time graph?
A body is thrown vertically upward with velocity u, the greatest height h to which it will rise is,
