Advertisements
Advertisements
प्रश्न
A body, initially at rest, starts moving with a constant acceleration 2 m s-2. Calculate: (i) the velocity acquired and (ii) the distance travelled in 5 s.
Advertisements
उत्तर
Initial velocity u = 0 m/s
Acceleration a = 2 m/s2
Time t = 5 s
(i) Let 'v' be the final velocity.
Then, (v - u)/5 = 2
v = 10 m/s-1
(ii) Let 's' be the distance travelled.
Using the third equation of motion,
v2 - u2 = 2as
We get,
(10) 2 - (0) 2 = 2(2) (s)
Thus, s = (100/4) m = 25 m
APPEARS IN
संबंधित प्रश्न
Give one example of a situation in which a body has a certain average speed but its average velocity is zero.
Fill in the following blank with suitable word :
A motorcycle has a steady……………. of 3 m/s2. This means that every………………. its…………….. increases by………….
Explain why, the motion of a body which is moving with constant speed in a circular path is said to be accelerated.
A train travelling at 20 m s-1 accelerates at 0.5 m s-2 for 30 s. How far will it travel in this time ?
A bus was moving with a speed of 54 km/h. On applying brakes it stopped in 8 seconds. Calculate the acceleration.
A boy is sitting on a merry-go-round which is moving with a constant speed of 10 m s−1. This means that the boy is :
Differentiate between uniform acceleration and variable acceleration.
A body starts from rest and acquires a velocity 10 m s-1 in 2 s. Find the acceleration.
The velocity-time graph of a body in motion is a straight line inclined to the time axis. The correct statement is ___________
How will the equations of motion for an object moving with a uniform velocity change?
