Advertisements
Advertisements
प्रश्न
The velocity-time graph (Fig. 8.5) shows the motion of a cyclist. Find (i) its acceleration (ii) its velocity and (iii) the distance covered by the cyclist in 15 seconds.
Advertisements
उत्तर
Velocity-time graph is a straight line parallel to the time axis, so, the velocity of the cyclist is constant.
(i) Acceleration = 0
(ii) At, f = 15 s velocity = 20 m s’1 (from the given graph)
(iii) Distance covered by the cyclist in 15 s
= Area under v - t graph during that time interval
= 20 ms’1 x 15 s
= 300 m.
APPEARS IN
संबंधित प्रश्न
A body starting from rest travels with uniform acceleration. If it travels 100 m in 5 s, what is the value of acceleration ?
Derive the formula s= `ut+1/2at^2` , where the symbols have usual meanings.
A boy is sitting on a merry-go-round which is moving with a constant speed of 10 m s−1. This means that the boy is :
The slope of a speed-time graph gives:
State how the velocity-time graph can be used to find
The acceleration of a body
For a uniformly retarded motion, the velocity-time graph is _____________
Multiple choice Question. Select the correct option.
The speed of a car reduces from 15 m/s to 5 m/s over a displacement of 10 m. The uniform acceleration of the car is :
Multiple choice Question. Select the correct option.
At the maximum height, a body thrown vertically upwards has :
Draw a velocity versus time graph of a stone thrown vertically upwards and then coming downwards after attaining the maximum height.
An object starting from rest travels 20 m in the first 2 s and 160 m in the next 4 s. What will be the velocity after 7 s from the start?
