Advertisements
Advertisements
प्रश्न
A motorcyclist drives from A to B with a uniform speed of 30 km h–1 and returns back with a speed of 20 km h–1. Find its average speed.
Advertisements
उत्तर
Let the distance between A and B be S km.
Time taken in going from A to B = `"s"/30 "h"`
Time taken in going from B to A = `"s"/20 "h"`
Average speed of motorcyclist = `"total distance covered"/"total time taken"`
= `("S km" + "S km")/("S"/30"h" + "S"/20"h")`
= `2/(1/30 + 1/20) "km h^-1"`
= `2/(1/12) "km h"^-1`
= 24 km h−1
APPEARS IN
संबंधित प्रश्न
What is the Differnece between speed and velocity ?
Arrange the following speed in increasing order (keeping the least speed first):
A bicycle moving with a speed of 200 m/min.
A car is moving along a straight road at a steady speed. It travels 150 m in 5 seconds:
What is its average speed ?
When is a body said to be in motion?
Express 15 m s-1 in km h-1.
A car moving on a straight path covers a distance of 1 km due east in 100 s. What is velocity of the car?
Draw the shape of the velocity-time graph for a body moving with (a) Uniform velocity and (b) Uniform acceleration.
Define average velocity and give one example.
Give two examples of uniform circular motion from your daily life.
Derive th e equation of motion.
S = ut+ `1/2` at2,
Where the symbols have their usual meanings
