Advertisements
Advertisements
प्रश्न
Figure shows the displacement of a body at different times .
Calculate the average velocity during the time interval 5 s to 9 s ,
[Hint : From 5 s to 9 s , displacement = 7 m - 3m = 4m]
Advertisements
उत्तर
From, 5 s to 9 s , displacement = 7m - 3m = 4m.
Time elapsed between 5 s to 9 s = 4 s
Average velocity = Displacement/time
= (4/4) m/s
= 1 m/s-1
APPEARS IN
संबंधित प्रश्न
Joseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back to point C in another 1 minute. What are Joseph’s average speeds and velocities in jogging?
- from A to B and
- from A to C?
Name the physical quantity which gives us an idea of how slow or fast a body is moving.
A car is moving along a straight road at a steady speed. It travels 150 m in 5 seconds:
How long does it take to travel 240 m ?
A car travels 100 km at a speed of 60 km/h and returns with a speed of 40 km/h. Calculate the average speed for the whole journey.
Write the formula to calculate the speed of a body moving along a circular path. Give the meaning of each symbol which occurs in it.
Give an example of the motion of a body moving with a constant speed but with a variable velocity. Draw a diagram to represent such a motion.
Arrange the following speeds in increasing order.
10 m s-1, 1 km min-1 and 18 km h-1.
A car travels the first 30 km with a uniform speed of 60 km h−1 and the next 30 km with a uniform speed of 40 km h−1. Calculate :
- The total time of journey,
- The average speed of the car.
Give two examples of uniform circular motion from your daily life.
Which of the following figures (Fig. 8.3) represents uniform motion of a moving object correctly?
