Advertisements
Advertisements
प्रश्न
Figure shows the displacement of a body at different times .
Calculate the average velocity during the time interval 5 s to 9 s ,
[Hint : From 5 s to 9 s , displacement = 7 m - 3m = 4m]
Advertisements
उत्तर
From, 5 s to 9 s , displacement = 7m - 3m = 4m.
Time elapsed between 5 s to 9 s = 4 s
Average velocity = Displacement/time
= (4/4) m/s
= 1 m/s-1
APPEARS IN
संबंधित प्रश्न
A train starting from Railway Station attains a speed of 21 m/s in one minute. Find its acceleration.
A motorcyclist drives from place A to B with a uniform speed of 30 km h-1 and returns from place B to A with a uniform speed of 20 km h-1. Find his average speed.
If a bus travelling at 20 m/s is subjected to a steady deceleration of 5 m/s2, how long will it take to come to rest ?
A car is moving along a straight road at a steady speed. It travels 150 m in 5 seconds:
How long does it take to travel 240 m ?
Which of the following can sometimes be 'zero' for a moving body?
(i) average velocity
(ii) distance travelled
(iii) average speed
(iv) displacement
What do you mean by motion in one direction?
Give an example of motion in which the average speed is not zero but the average velocity is zero.
The velocity-time graph of a moving body is given below in Figure
Total displacement.
A train travels with a speed of 60 km h-1 from station A to station B and then comes back with a speed 80 km h-1 from station B to station A. Find -
- The average speed
- The average velocity of the train.
Give two examples of uniform circular motion from your daily life.
