Advertisements
Advertisements
प्रश्न
Figure shows the displacement of a body at different times .
Calculate the velocity of the body as it moves for time interval :
(i) 0 to 5 s,
(ii) 5 s to 7 s
(iii) 7 s to 9 s.
Advertisements
उत्तर
(a) (i) Velocity from 0 to 5 s = Displacement /time
= (3/5) m/s
= 0.6 m/s-1
(ii) Velocity from 5 s to 7 s = Displacement /time
= (0/2) m/s
= 0 m/s-1.
(iii) Velocity from 7 s to 9 s = Displacement /time
= (7 - 3)/(9 - 7) m/s
= (4/2) m/s
= 2 m/s-1
APPEARS IN
संबंधित प्रश्न
Under what condition(s) is the magnitude of average velocity of an object equal to its average speed?
An aircraft travelling at 600 km/h accelerates steadily at 10 km/h per second. Taking the speed of sound as 1100 km/h at the aircraft’s altitude, how long will it take to reach the ‘sound barrier’ ?
The graph given alongside shows how the speed of a car changes with time:
(i) What is the initial speed of the car ?
(ii) What is the maximum speed attained by the car ?
(iii) Which part of the graph shows zero acceleration ?
(iv) Which part of the graph shows varying retardation ?
(v) Find the distance travelled in first 8 hours.
Give one example of following motion :
Uniform velocity
Give one example of following motion :
Variable velocity
A car travels the first 30 km with a uniform speed of 60 km h−1 and the next 30 km with a uniform speed of 40 km h−1. Calculate :
- The total time of journey,
- The average speed of the car.
For the motion with uniform velocity , how is the distance travelled related to the time ?
Draw the shape of the velocity-time graph for a body moving with (a) Uniform velocity and (b) Uniform acceleration.
Define variable velocity and give one example.
Distinguish between speed and velocity.
