Advertisements
Advertisements
प्रश्न
Figure shows the displacement of a body at different times .
Calculate the velocity of the body as it moves for time interval :
(i) 0 to 5 s,
(ii) 5 s to 7 s
(iii) 7 s to 9 s.
Advertisements
उत्तर
(a) (i) Velocity from 0 to 5 s = Displacement /time
= (3/5) m/s
= 0.6 m/s-1
(ii) Velocity from 5 s to 7 s = Displacement /time
= (0/2) m/s
= 0 m/s-1.
(iii) Velocity from 7 s to 9 s = Displacement /time
= (7 - 3)/(9 - 7) m/s
= (4/2) m/s
= 2 m/s-1
APPEARS IN
संबंधित प्रश्न
Under what condition(s) is the magnitude of average velocity of an object equal to its average speed?
State whether speed is a scalar or a vector quantity. Give reason for your choice.
Arrange the following speed in increasing order (keeping the least speed first):
A bicycle moving with a speed of 200 m/min.
Write the formula for acceleration. Give the meaning of each symbol which occurs in it.
Convert a speed of 54 km/h into m/s.
Which of the following statement is correct regarding velocity and speed of a moving body?
Express 15 m s-1 in km h-1.
Draw the shape of the velocity-time graph for a body moving with (a) Uniform velocity and (b) Uniform acceleration.
A body projected vertically up with a velocity of 10 m/s reaches a height of 20 m. If it is projected with a velocity of 20 m/s, then the maximum height reached by the body is:
Write down the type of motion of a body along with the A – O – B of the following distance – time graph.
