Advertisements
Advertisements
Question
Figure shows the displacement of a body at different times .
Calculate the velocity of the body as it moves for time interval :
(i) 0 to 5 s,
(ii) 5 s to 7 s
(iii) 7 s to 9 s.
Advertisements
Solution
(a) (i) Velocity from 0 to 5 s = Displacement /time
= (3/5) m/s
= 0.6 m/s-1
(ii) Velocity from 5 s to 7 s = Displacement /time
= (0/2) m/s
= 0 m/s-1.
(iii) Velocity from 7 s to 9 s = Displacement /time
= (7 - 3)/(9 - 7) m/s
= (4/2) m/s
= 2 m/s-1
APPEARS IN
RELATED QUESTIONS
Joseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back to point C in another 1 minute. What are Joseph’s average speeds and velocities in jogging?
- from A to B and
- from A to C?
A motorcyclist drives from place A to B with a uniform speed of 30 km h-1 and returns from place B to A with a uniform speed of 20 km h-1. Find his average speed.
A car is moving along a straight road at a steady speed. It travels 150 m in 5 seconds:
How long does it take to travel 240 m ?
Which of the following could not be a unit of speed?
Give one example of following motion :
Uniform velocity
A car moving on a straight path covers a distance of 1 km due east in 100 s. What is the speed of the car?
A car accelerates at a rate of 5 m s-2. Find the increase in its velocity in 2 s.
A car is moving with a velocity 20 m s-1. The brakes are applied to retard it at a rate of 2 m s-2. What will be the velocity after 5 s of applying the brakes?
For the motion with uniform velocity , how is the distance travelled related to the time ?
A train is moving with a velocity of 90 km h-1 . It is brought to stop by applying the brakes which produce a retardation of 0.5 ms-2 Find :
(i) The velocity after 10 s , and
(ii) the time taken by the train to come to rest .
