Advertisements
Advertisements
प्रश्न
A body is moving in a straight line and its displacement at various instants of time is given in the following table
| Time (s) | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| Displacement (m) | 2 | 6 | 12 | 12 | 12 | 18 | 22 | 24 |
Plot the displacement-time graph and calculate
(i) Total distance travelled in the interval 1 s to 5 s.
(ii) Average velocity in time interval 1 s to 5 s.
Advertisements
उत्तर

(i) Total distance travelled in interval 1s to 5s = 18m - 6m = 12 m.
(ii) Average velocity = Total displacement in the given time interval/Time interval, i.e. 1 s to 5 s.
Or, Average velocity = 12 m/4 s = 3 m/s.
APPEARS IN
संबंधित प्रश्न
The displacement of a moving object in a given interval of time is zero. Would the distance travelled by the object also be zero ? Give reason for your answer.
Is displacement a scalar quantity?
Define displacement. State its unit.
What information about the motion of a body are obtained from the displacement-time graph?
How is the distance related with time for motion under uniform acceleration such as the motion of a freely falling body?
How can you find the following?
Velocity from a displacement – time graph.
Can you suggest the kind of motion of a body from the following distance – time graph?

Can you suggest the kind of motion of a body from the following distance – time graph?

A body moves is a circle of radius ‘2R’ what is the distance covered and displacement of the body after 2 complete rounds?
Obtain a relation for the distance travelled by an object moving with uniform acceleration in the interval between 4th and 5th seconds.
