Advertisements
Advertisements
प्रश्न
Figure shows the displacement of a body at different times .
Calculate the average velocity during the time interval 5 s to 9 s ,
[Hint : From 5 s to 9 s , displacement = 7 m - 3m = 4m]
Advertisements
उत्तर
From, 5 s to 9 s , displacement = 7m - 3m = 4m.
Time elapsed between 5 s to 9 s = 4 s
Average velocity = Displacement/time
= (4/4) m/s
= 1 m/s-1
APPEARS IN
संबंधित प्रश्न
Under what condition(s) is the magnitude of average velocity of an object equal to its average speed?
The tip of seconds’ hand of a dock takes 60 seconds to move once on the circular dial of the clock. If the radius of the dial of the clock be 10.5 cm, calculate the speed of the tip of the seconds’ hand of the clock. `("Given" π= 22/7)`.
A bus moving along a straight line at 20 m/s undergoes an acceleration of 4 m/s2. After 2 seconds, its speed will be:
Give one example of following motion :
Variable velocity
The speed of a car is 72 km h-1. Express it in m s-1.
Arrange the following speeds in increasing order.
10 m s-1, 1 km min-1 and 18 km h-1.
A car moving on a straight path covers a distance of 1 km due east in 100 s. What is velocity of the car?
A car accelerates at a rate of 5 m s-2. Find the increase in its velocity in 2 s.
Draw a diagram to show the motion of a body whose speed remains constant, but velocity changes continuously.
A speeding car changes its velocity from 108 kmh−1 to 36 kmh−1 in 4 s. Calculate its deceleration in
- ms−2
- kmh−2.
