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प्रश्न
A girl walks along a straight path to drop a letter in the letterbox and comes back to her initial position. Her displacement–time graph is shown in Fig.8.4. Plot a velocity-time graph for the same.
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उत्तर
From displacement – time graph,
velocity = `"displacement"/"time"`
= `(100"m")/(50"s")`
= 2ms−1
The symmetry of the graph shows that the girl comes back to her initial position with the same velocity (2 ms−1) but in opposite direction. So, the velocity-time graph will look like
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संबंधित प्रश्न
Name the physical quantity whose SI unit is :
(a) m/s (b) m/s2
What is meant by the term acceleration ? State the SI unit of acceleration.
Name the quantity which is measured by the area occupied under the velocity-time graph.
Explain why, the motion of a body which is moving with constant speed in a circular path is said to be accelerated.
A bus running at a speed of 18 km/h is stopped in 2.5 seconds by applying brakes. Calculate the retardation produced.
Define velocity. State its unit.
A body starts from rest and acquires a velocity 10 m s-1 in 2 s. Find the acceleration.
State how the velocity-time graph can be used to find
The acceleration of a body
A body, initially at rest, starts moving with a constant acceleration 2 m s-2. Calculate: (i) the velocity acquired and (ii) the distance travelled in 5 s.
When will you say a body is at uniform acceleration?
