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Question
A motor bike running at 5 ms−1, picks up a velocity of 30 ms−1 in 5s. Calculate
- acceleration
- distance covered during acceleration.
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Solution
Initial velocity of motor bike = u = 5 ms−1
Final velocity of motor bike = v = 30 ms−1
Time = t = 5 s
(i) Acceleration = a = ?
v = u + at
30 = 5 + a (5)
5a = 30 − 5 = 25
a = `25/5` = 5 ms−2
(ii) Distance covered S =?
S = ut + `1/2` at2
S = `5(5)+1/2(5)(5)^2`
S = `25+125/2` = 25 + 62.5
S = 87.5 m
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