Advertisements
Advertisements
Question
A ball moves on a smooth floor in a straight line with uniform velocity 10 m s-1 for 6 s. At t = 6 s, the ball hits a wall and comes back along the same line to the starting point with the same speed. Draw the velocity-time graph and use it to find the total distance travelled by the ball and its displacement.
Advertisements
Solution
Distance travelled in first 6 s = velocity × time
= 10 m/s × 6
= 60 m
Distance travelled in next 6 s = velocity × time
= 10 m/s × 6
= 60 m
Total distance travelled in 12 s = (60 + 60) m = 120 m
Total displacement = 0, as the ball returns its starting point.
APPEARS IN
RELATED QUESTIONS
State how the velocity-time graph can be used to find The distance travelled by the body in a given time
What can you say about the nature of motion of a body if its displacement-time graph is A straight line parallel to the time axis?
The following table gives the displacement of a car at different instants of time.
| Time (s) | 0 | 1 | 2 | 3 | 4 |
| Displacement (m) | 0 | 5 | 10 | 15 | 20 |
- Draw the displacement-time sketch and find the average velocity of the car.
- What will be the displacement of the car at (i) 2.5 s and (ii) 4.5 s?
A body starts with an initial velocity of 10m s-1 and acceleration 5 m s-2. Find the distance covered by it in 5 s.
Copy the following table and fill in the blank spaces.
| Quantity | S.I. Unit | Scalar or Vector |
| Displacement | ___________ | ___________ |
Define displacement.
Write the SI units for measurement of distance and displacement.
A 50 m long train passes over a bridge at a speed of 30 km/h. If it takes 36 seconds to cross the bridge, calculate the length of the bridge.
The table below shows the distance travelled by two vehicles A and B during each second:
| Time (s) | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| Distance travelled by A (m) | 0 | 20 | 80 | 180 | 240 | 300 | 360 | 420 |
| Distance travelled by B (m) | 0 | 10 | 40 | 90 | 160 | 250 | 360 | 490 |
Give the value of the velocity at which they are meeting
An object is dropped from rest at a height of 150 m and simultaneously another object is dropped from rest at a height of 100 m. What is the difference in their heights after 2s if both the objects drop with the same accelerations? How does the difference in heights vary with time?
