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Question
A ball moves on a smooth floor in a straight line with uniform velocity 10 m s-1 for 6 s. At t = 6 s, the ball hits a wall and comes back along the same line to the starting point with the same speed. Draw the velocity-time graph and use it to find the total distance travelled by the ball and its displacement.
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Solution
Distance travelled in first 6 s = velocity × time
= 10 m/s × 6
= 60 m
Distance travelled in next 6 s = velocity × time
= 10 m/s × 6
= 60 m
Total distance travelled in 12 s = (60 + 60) m = 120 m
Total displacement = 0, as the ball returns its starting point.
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RELATED QUESTIONS
Give two differences between displacement and distance.
Draw displacement – time graph for the following situation:
When a body is moving with uniform velocity.
From the displacement – time graph shown given below calculate :
- Velocity between 0 – 2 s.
- Velocity between 8 s – 12 s.
- Average velocity between 5 s – 12 s.
The shortest distance between two places is ______.
Fill in the boxes.
| S.No | First Move | Seconde Move | Distance (m) | Displacement |
| 1. | Move 4 metres east | Move 2 metres west | 6 | 2 m east |
| 2. | Move 4 metres north | Move 2 metres south | ||
| 3. | Move 2 metres east | Move 4 metres west | ||
| 4. | Move 5 metres east | Move 5 metres west | ||
| 5. | Move 5 metres south | Move 2 metres north | ||
| 6. | Move 10 metres west | Move 3 metres east |
Is displacement a scalar quantity?
The rate of change of displacement ______.
A scalar quantity has ______.
The displacement covered by the second hand of radius V in a clock after one revolution is ______.
Assertion: If the displacement of the body is zero, the distance covered by it may not be zero.
Reason: Displacement is a vector & distance is a scalar quantity.
