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प्रश्न
A ball moves on a smooth floor in a straight line with uniform velocity 10 m s-1 for 6 s. At t = 6 s, the ball hits a wall and comes back along the same line to the starting point with the same speed. Draw the velocity-time graph and use it to find the total distance travelled by the ball and its displacement.
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उत्तर
Distance travelled in first 6 s = velocity × time
= 10 m/s × 6
= 60 m
Distance travelled in next 6 s = velocity × time
= 10 m/s × 6
= 60 m
Total distance travelled in 12 s = (60 + 60) m = 120 m
Total displacement = 0, as the ball returns its starting point.
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संबंधित प्रश्न
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