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प्रश्न
Geetha takes 15 minutes from her house to reach her school on a bicycle. If the bicycle has a speed of 2 m/s, calculate the distance between her house and the school.
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उत्तर
Given : time taken = 15 minutes [1 min = 60 sec]
= 15 x 60 = 900 sec
Speed – 2 m/s
Distance = ?
Formula :
Distance = Speed x time
= 2 x 900
Distance between her house and the school = 1,800 m
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संबंधित प्रश्न
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Clarify the difference.
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| Time (s) | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| Displacement (m) | 2 | 6 | 12 | 12 | 12 | 18 | 22 | 24 |
Plot the displacement-time graph and calculate
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(ii) Average velocity in time interval 1 s to 5 s.
A car travels a distance 100 m with constant acceleration and average velocity of 20 ms-1. The final velocity acquired by the car is 25 ms-1.
Find
(i) The initial velocity.
(ii) Acceleration of the car.
An object is thrown vertically upwards. It rises upto a height H and then returns to its initial position. Calculate
The displacement of the object.
Match the following.
| 1. | Displacement | Knot |
| 2. | Light travelling through vacuum | Geometric centre |
| 3. | Speed of ship | Metre |
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| 5. | Stability | Uniform velocity |
Exercise Problems.
An athlete completes one round of a circular track of diameter 200 m in 40 s. What will be the distance covered and the displacement at the end of 2 m and 20 s?
The SI unit of displacement is ______.
The displacement of a moving object in a given interval of time is zero. Would the distance travelled by the object also be zero? Justify your answer.
Obtain a relation for the distance travelled by an object moving with uniform acceleration in the interval between 4th and 5th seconds.
