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प्रश्न
From the displacement – time graph shown given below calculate :
- Velocity between 0 – 2 s.
- Velocity between 8 s – 12 s.
- Average velocity between 5 s – 12 s.

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उत्तर
1. Velocity between 0 – 2 s = `(-(25-10))/2` .......[negative sign because slope is negative]
= `-15/2`
= −7.5 ms−1
2. Velocity between 8 s – 12 s = `(25-20)/(12-8)=5/4`
= 1.25 ms−1
3. Average velocity between 5 s – 12 s
= `"Total displacement from 5 s to 12 s"/"Time"`
= `(25-10)/(12-5)`
= `15/7`
= 2.1 ms−1
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संबंधित प्रश्न
In which of the following cases of motion, the distance moved and the magnitude of displacement are equal?
State how the velocity-time graph can be used to find The distance travelled by the body in a given time
From the displacement – time graph shown given below calculate:
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- Displacement from the initial position at the end of 13 s.
- Time after which the body is at the initial position,
- Average velocity after 8 s.

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A body is moving along a circular path of radius r. What will be the distance and displacement of the body when it completes:
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Distance covered by a particle never becomes zero but displacement becomes zero.
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Give one example where the displacement is zero but the distance travelled is not zero.
Choose the correct option.
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