Advertisements
Advertisements
प्रश्न
From the displacement – time graph shown given below calculate:
- Average velocity in the first three seconds.
- Displacement from the initial position at the end of 13 s.
- Time after which the body is at the initial position,
- Average velocity after 8 s.

Advertisements
उत्तर
(i) In first three seconds
Total displacement = 8m
Total time = 3 s
Average velocity = Total displacement/Total time = 8/3
= 2.67 ms−1
(ii) Displacement from the initial position at the end of 13s = −8m.
(iii) Body is at the initial position after 8s and 17s.
(iv) Average velocity after 8s is zero because, after 8s, displacement is zero.
APPEARS IN
संबंधित प्रश्न
Under what conditions can a body travel a certain distance and yet its resultant displacement be zero ?
If on a round trip you travel 6 km and then arrive back home :
What distance have you travelled ?
A train takes 3 h to travel from Agra to Delhi with a uniform speed of 65 km h-1. Find the distance between the two cities.
What can you say about the nature of motion of a body if its displacement-time graph is A straight line inclined to the time axis with an acute angle?
Give an example of a body which covers a certain distance, but its displacement is zero.
Draw displacement – time graph for the following situation:
When a body is moving with uniform velocity.
Can you suggest the kind of motion of a body from the following distance – time graph?

Exercise Problems.
An athlete completes one round of a circular track of diameter 200 m in 40 s. What will be the distance covered and the displacement at the end of 2 m and 20 s?
Four cars A, B, C, and D are moving on a levelled road. Their distance versus time graphs are shown in Fig. 8.2. Choose the correct statement.

Give one example where the displacement is zero but the distance travelled is not zero.
