Advertisements
Advertisements
प्रश्न
The probability density plots of 1s and 2s orbitals are given in Figure:
The density of dots in a region represents the probability density of finding electrons in the region.
On the basis of above diagram which of the following statements is incorrect?
पर्याय
1s and 2s orbitals are spherical in shape.
The probability of finding the electron is maximum near the nucleus.
The probability of finding the electron at a given distance is equal in all directions.
The probability density of electrons for 2s orbital decreases uniformly as distance from the nucleus increases.
Advertisements
उत्तर
The probability density of electrons for 2s orbital decreases uniformly as distance from the nucleus increases.
Explanation:
As per the probability density curve, the probability of finding the electrons at the 1s orbital decreases as we move far from the nucleus, however in case of 2s the probability decreases initially then it increases with the distance and thereafter at a certain point it starts decreasing with the distance.
APPEARS IN
संबंधित प्रश्न
Using s, p, d notations, describe the orbital with the following quantum numbers n = 1, l = 0.
Choose the correct option.
Principal Quantum number describes -
State Hund’s rule of maximum multiplicity with a suitable example.
State the order of filling atomic orbitals following Aufbau principle.
Explain the anomalous behaviour of copper.
Write orbital notations for the electron in orbitals with the following quantum numbers.
n = 4, l = 2
Write condensed orbital notation of electronic configuration of the following element:
Carbon (Z = 6)
Draw shapes of 2s orbitals.
Explain in brief, the significance of the azimuthal quantum number.
The designation of a subshell with n = 6 and l = 2 is ____________.
The number of radial nodes for 3p orbital is ______.
Total number of orbitals associated with third shell will be ______.
In which of the following pairs, the ions are iso-electronic?
(i) \[\ce{Na^{+}, Mg^{2+}}\]
(ii) \[\ce{Al3^{+}, O-}\]
(iii) \[\ce{Na+ , O2-}\]
(iv) \[\ce{N3-, Cl-}\]
Nickel atom can lose two electrons to form \[\ce{Ni^{2+}}\] ion. The atomic number of nickel is 28. From which orbital will nickel lose two electrons.
The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.
Based upon the above information, arrange the following orbitals in the increasing order of energy.
5p, 4d, 5d, 4f, 6s
The electronic configuration of valence shell of Cu is 3d104s1 and not 3d94s2. How is this configuration explained?
Which of the following is the correct plot for the probability density ψ2 (r) as a function of distance 'r' of the electron from the nucleus for 2s orbitals?
In assigning R - S configuration, which among the following groups has highest priority?
