Advertisements
Advertisements
Question
The probability density plots of 1s and 2s orbitals are given in Figure:

The density of dots in a region represents the probability density of finding electrons in the region.
On the basis of above diagram which of the following statements is incorrect?
Options
1s and 2s orbitals are spherical in shape.
The probability of finding the electron is maximum near the nucleus.
The probability of finding the electron at a given distance is equal in all directions.
The probability density of electrons for 2s orbital decreases uniformly as distance from the nucleus increases.
Advertisements
Solution
The probability density of electrons for 2s orbital decreases uniformly as distance from the nucleus increases.
Explanation:

As per the probability density curve, the probability of finding the electrons at the 1s orbital decreases as we move far from the nucleus, however in case of 2s the probability decreases initially then it increases with the distance and thereafter at a certain point it starts decreasing with the distance.
APPEARS IN
RELATED QUESTIONS
State Heisenberg uncertainty principle.
Give the names of quantum numbers.
Write condensed orbital notation of electronic configuration of the following element:
Oxygen (Z = 8)
Write condensed orbital notation of electronic configuration of the following element:
Chlorine (Z = 17)
Indicate the number of unpaired electron in:
Cr (Z = 24)
The principal quantum number (n) and magnetic quantum number (ml) for the valence electrons of rubidium atom (Z = 37) are ____________ respectively.
The designation of a subshell with n = 6 and l = 2 is ____________.
How many electrons in 19K have n = 3, l = 1?
How many electrons can fit in the orbital for which n = 4 and l = 2?
Which one of the following is NOT possible?
Number of angular nodes for 4d orbital is ______.
Orbital angular momentum depends on ______.
Nickel atom can lose two electrons to form \[\ce{Ni^{2+}}\] ion. The atomic number of nickel is 28. From which orbital will nickel lose two electrons.
The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.
Based upon the above information, arrange the following orbitals in the increasing order of energy.
4s, 3s, 3p, 4d
The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.
Based upon the above information, solve the questions given below:
Which of the following orbitals has the lowest energy?
4d, 4f, 5s, 5p
Match species given in Column I with the electronic configuration given in Column II.
| Column I | Column II |
| (i) \[\ce{Cr}\] | (a) [Ar]3d84s0 |
| (ii) \[\ce{Fe^{2+}}\] | (b) [Ar]3d104s1 |
| (iii) \[\ce{Ni^{2+}}\] | (c) [Ar]3d64s0 |
| (iv) \[\ce{Cu}\] | (d) [Ar] 3d54s1 |
| (e) [Ar]3d64s2 |
Which of the following is the correct plot for the probability density ψ2 (r) as a function of distance 'r' of the electron from the nucleus for 2s orbitals?
Which one of the following laws will represent the pairing of electrons in a subshell after each orbital is filled with one electron?
